If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10x^2-100x+9=0
a = 10; b = -100; c = +9;
Δ = b2-4ac
Δ = -1002-4·10·9
Δ = 9640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9640}=\sqrt{4*2410}=\sqrt{4}*\sqrt{2410}=2\sqrt{2410}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-2\sqrt{2410}}{2*10}=\frac{100-2\sqrt{2410}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+2\sqrt{2410}}{2*10}=\frac{100+2\sqrt{2410}}{20} $
| 1/2(y-8)=-3.5+8 | | 8r+10=50 | | (x)=3x2+12x+5 | | 9+4n=-27 | | x/2=13=15 | | 9n-5=94 | | -8k+3=125 | | −8|x|−8=−32 | | 2739=33(p+30) | | x+(-3.9)=4.1 | | -(12+t)=44 | | 6(x+4)+4=-10(x-4)-1 | | 7y=22=71 | | 3x-3=3x+24 | | -×-23=3x+5 | | 2n+20=4n+16 | | 23x+5=-5+25x | | z÷3-2z+4(z-8)z=18 | | 21x+8=113 | | 3(6-4x)=-2(6x-9 | | 2+k=5/3 | | 2 = q4− 1 | | 4x+3=5x-2+1 | | 7r+7=21 | | 4(x+3)-4=8(1/2x+) | | 3(6-4x)=-2(6+-9 | | (12+z)-4=20 | | -2x=23=5 | | 0.1(x+91)=-2(4-x) | | 9(z−94)=27 | | -2x=23= | | 2x*x+8=0 |